b^2-3b+5-(b^2+5b+6)=

Solution for b^2-3b+5-(b^2+5b+6)= equation:

Simplifying
b2 + -3b + 5 + -1(b2 + 5b + 6) = 0

Reorder the terms:
b2 + -3b + 5 + -1(6 + 5b + b2) = 0
b2 + -3b + 5 + (6 * -1 + 5b * -1 + b2 * -1) = 0
b2 + -3b + 5 + (-6 + -5b + -1b2) = 0

Reorder the terms:
5 + -6 + -3b + -5b + b2 + -1b2 = 0

Combine like terms: 5 + -6 = -1
-1 + -3b + -5b + b2 + -1b2 = 0

Combine like terms: -3b + -5b = -8b
-1 + -8b + b2 + -1b2 = 0

Combine like terms: b2 + -1b2 = 0
-1 + -8b + 0 = 0
-1 + -8b = 0

Solving
-1 + -8b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -8b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -8b = 0 + 1
-8b = 0 + 1

Combine like terms: 0 + 1 = 1
-8b = 1

Divide each side by '-8'.
b = -0.125

Simplifying
b = -0.125